14x^2-10x-2320=0

Solution for 14x^2-10x-2320=0 equation:

14x^2-10x-2320=0

a = 14; b = -10; c = -2320;
Δ = b2-4ac
Δ = -102-4·14·(-2320)
Δ = 130020
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{130020}=\sqrt{4*32505}=\sqrt{4}*\sqrt{32505}=2\sqrt{32505}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{32505}}{2*14}=\frac{10-2\sqrt{32505}}{28}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{32505}}{2*14}=\frac{10+2\sqrt{32505}}{28}
$